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+//Book Name:Fundamentals of Electrical Engineering
+//Author:Rajendra Prasad
+//Publisher: PHI Learning Private Limited
+//Edition:Third ,2014
+
+//Ex3_22.sce.
+
+clc;
+clear;
+V=230;   //Supply voltage in volt
+PL1=10E3;  //supply power to loaad 1 in watt 
+pf1=0.7;// lagging power factor value of load 1
+P2=10E3;   //supply power  to load 2 in watt
+pf2=0.5;  //lagging power factor value of load 2
+
+printf("\n (a)")
+PL2=P2*pf2;
+QL1=PL1*tand(acosd(pf1));
+QL2=PL2*tand(acosd(pf2));
+PL=PL1+PL2;
+QL=QL1+QL2;
+QC=-QL;
+IC=QC/V;
+XC=QC/IC^2;
+f=50;
+C=1/(2*%pi*f*-XC);
+printf("\n     The value of capacitance=%4.1f micro-farad \n",C*1e6)
+
+printf("\n (b)\t(i)")
+kVA=sqrt(PL^2+QL^2);
+Ig=kVA/V;
+printf("\n    Magnitude alternator current without capacitor=%3.1f A \n",Ig)
+printf("\n\t(ii)")
+kVA=PL;
+Ig=kVA/V;
+printf("\n    Magnitude alternator current with capacitor=%2.1f A \n",Ig)
+//Answer vary dueto roundoff error