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+//Book Name:Fundamentals of Electrical Engineering
+//Author:Rajendra Prasad
+//Publisher: PHI Learning Private Limited
+//Edition:Third ,2014
+
+//Ex11_4.sce
+
+clc;
+clear;
+P=200;
+V=100;
+N=1500;
+Ka=525;
+Ra=2;
+Pl=15;
+
+Pd=P+Pl;
+n=N/60;
+Td=Pd/(2*%pi*n);
+//n=(Va/(Ka*phi_p))-(2*%pi*Ra*Td/(Ka*phi_p)^2);
+//from this equation we get phi^2-o-0.0076*phi+2.5e-6=0;
+a=1;
+b=-0.0076;//a,b,c are coefficient values taken from the above second order equation
+c=2.5e-6;
+phi_p=(-b+sqrt(b^2-(4*a*c)))/(2*a);
+printf("\n The magnetic flux=%1.3f mWb \n",phi_p*1000)