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+//Book Name:Fundamentals of Electrical Engineering
+//Author:Rajendra Prasad
+//Publisher: PHI Learning Private Limited
+//Edition:Third ,2014
+
+//Ex10_3.sce
+
+clc;
+clear;
+Pin=40;  // power in kW
+Ps=1.5;   // power in kW
+Ns=100;             //speed percentage value
+N=40;               //speed percentage value
+power_loss=0.8;        // power in kW
+
+printf("\n (a)")
+rotor_input_power=Pin-Ps;
+s=0.04;
+rotor_copper_loss=s*rotor_input_power;
+mec_power_developed=rotor_input_power-rotor_copper_loss;
+printf("\n  Mechanical power developed by the rotor=%2.2f kW",mec_power_developed)
+printf("\n  Rotor copper loss=%2.2f kW \n",rotor_copper_loss)
+
+printf("\n (b)")
+motor_output_power=mec_power_developed-power_loss;
+printf("\n  Output of the motor=%2.2f kW \n",motor_output_power)
+
+printf("\n (c)")
+motor_efficiency=(motor_output_power/Pin)*100;
+printf("\n  The motor efficiency=%2.1f percentage \n",motor_efficiency)
+
+printf("\n (d)")
+new_slip=(Ns-N)/Ns;
+total_rotor_copper_loss=new_slip*rotor_input_power;
+printf("\n  Total rotor copper loss when speed reduced to 40percentage of synchronous speed=%2.1f kW \n",total_rotor_copper_loss)
+
+printf("\n (e)")
+total_rotor_loss=total_rotor_copper_loss+power_loss;
+motor_output_power=rotor_input_power-total_rotor_loss;
+motor_efficiency=(motor_output_power/Pin)*100;
+printf("\n  Efficiency of motor when speed reduced to 40percentage of synchronous speed=%2.1f percentage",motor_efficiency)