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+// Example 2_2
+clc;funcprot(0);
+// Given data
+v_x=50;// The initial velocity in ft/sec
+a_x=-10;// The acceleration in ft/sec^2
+t_0=8;// s
+t_1=12;// s
+
+// Calculation
+// v_x=90-10t; ft/sec
+v_x0=(90-(10*t_0));// The velocity in ft/sec
+v_x1=(90-(10*t_1));// The velocity in ft/sec
+// x=-5t^2+90t-80; ft
+x_0=(-5*t_0^2)+(90*t_0)-80;// ft
+x_1=(-5*t_1^2)+(90*t_1)-80;// ft
+// The maximum positive x-coordinate is,then, the value of x for t=9 sec which is
+t=9;// sec
+x_max=(-5*t^2)+(90*t)-80;// ft
+printf("\nThe velocity of the particle for the conditions of t=8 sec and t=12 sec,v_x=%2.0f ft/sec & v_x=%2.0f ft/sec \nThe x-coordinate of the particle for the conditions of t=8 sec and t=12 sec, x=%3.0f ft & x=%3.0f ft \nThe maximum positive x-coordinate reached by the particle,x_max=%3.0f ft",v_x0,v_x1,x_0,x_1,x_max)