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+clc
+//variable initialisation
+Vph=2200 //Supply Voltage in volt
+F=50 //supply frequency in Hz
+Pout=2600 // Output Of Motor In KW
+P=8 //Number Of Poles
+N1=735 //Speed OF Motor In rpm
+Rs=0.075 //Resistance of stator in ohm
+Rr=0.1 //Resistance of rotor in ohm
+Xs=0.45 //Reactance of Motor in ohm
+Xr=0.55 //Reactance of Motor in ohm
+
+//Solution
+Ns=(120*F)/P
+S=(Ns-N1)/Ns
+Iph=Vph/sqrt((Rs+((Rr/S)^2))+((Xs+Xr)^2))
+Il=sqrt(3)*Iph
+Wms=(2*%pi*Ns)/60
+Tl=(3*((Iph)^2))/(S*(Wms))
+Ilm=Vph/(sqrt(3)*sqrt(((Rs+Rr)^2)+((Xs+Xr)^2)))
+S2=1
+Tst=(3*(((Ilm)^2)*0.1))/(S2*Wms)
+r1=Tst/Tl//ratio of Tst and Tl
+Tmax=(3/(2*Wms))*(((Vph/sqrt(3))^2)/((Rs+sqrt((Rs^2)+((Xs+Xr)^2)))))
+r2=Tmax/Tl//ratio of Tmax and Tl
+Rr2=0.15
+Xr2=0.9
+Il1=(sqrt(3)*Vph)/(sqrt(((Rs+Rr)^2)+((Xs+Xr2)^2)))
+Iph1=Il1/(sqrt(3))
+Tst1=(3*((Iph1)^2)*(Rr))/(Wms)
+Rs1=Rs/3
+Rr1=Rr/3
+Xs1=Xs/3
+Xr1=Xr/3
+Inew=2*Il
+X=sqrt(((Vph/(sqrt(3)*Inew))^2)-((Rs1+Rr1)^2))
+Xe=X-Xs1-Xr1
+printf('\n\n Ratio of starting torque and load torque=%0.1f \n\n',r1)//The answer provided in the textbook is wrong
+printf('\n\n Ratio of maximum torque and load torque=%0.1f \n\n',r2)
+printf('\n\n The Maximum line current during starting=%0.1f Amp\n\n',Il1)//The answer provided in the textbook is wrong
+printf('\n\n The maximum torque at starting=%0.1f N-m\n\n',Tst1)//The answer provided in the textbook is wrong
+printf('\n\n The required value of reactor=%0.1f ohm\n\n',Xe)