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+clc
+//variable initialisation
+Pout=37.3 //Motor Output In KW
+Vm=440 //Motor Input in volt
+F=50 //supply frequency in Hz
+I0=20 //NO Load Line Current Of Motor
+R1=0.1 //resistance of stator in ohm
+R2=0.15 //resistance of rotor in ohm
+X1=0.4 //reactance of Motor in ohm
+X2=0.44 //reactance of Motor in ohm
+S=0.03 //Slip Of Motor
+Ls=1250 //Stator Core Loses In Watt
+Lr=1000 //Rotational Losses In KW
+Ns=1500 // Synchronous Speed Of Motor
+
+//Solution
+Vph=Vm/sqrt(3)
+I2=Vph/((R1+(R2/S))+%i*(X1+X2))
+I21=abs(I2)
+I21=49.1//rounding off to avoid computational error
+I0=1.78-(%i*19.9)//Taken in book for No load motor current
+I1=I0+I2
+y=imag(I1)
+x=real(I1)
+phi=atand(y/x)
+pf=cosd(phi)
+P2=3*((I21)^2)*(R2/S)
+Tg=(9.55*P2)/Ns
+Pm=(1-S)*P2
+Pout1=Pm+Lr
+Lcs=3*((I21)^2)*R1//Wrong value of I2 is taken in textbook
+Lcr=S*P2
+Lt=Ls+Lr+Lcs+Lcr
+Pin=Lt+Pout1
+n=Pout1/Pin
+printf('\n\n The input line Current=%0.1f Amp\n\n',I1)
+printf('\n\n The power factor=%0.1f lag\n\n',pf)
+printf('\n\n The Electromagnetic Torque Developed=%0.1f N-m\n\n',Tg)
+printf('\n\n The output=%0.1f Watts\n\n',Pm)
+printf('\n\n The efficiency of Motor=%0.1f\n\n',n)
+//The answers vary due to round off error