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+
+clc
+//variable Initialisation
+Vm=400 //Terminal Voltage Of Motor In Volts
+Pout=3 //Output Of Motor In KW
+F=50 //Supply Frequency
+P=4 //Number Of Pole
+R1=2.5 //Resistance Of Motor in Ohm
+R2=4.5 //Resistance Of Motor in Ohm
+X1=6 //Reactance in Ohm
+X2=6 //Reactance in Ohm
+Nr1=1400 //Speed Of Rotor In RPM
+Nr2=1300 //Speed Of Rotor In RPM
+
+//Solution
+Ns=(120*F)/(P)
+S=(Ns-Nr1)/Ns
+Vph=Vm/sqrt(3)
+I2=(Vm)/sqrt(((R1+(R2/S))^2)+((X1+X2)^2))
+Ws=((2*%pi)/60)*(Ns)
+Tl=((3*((I2)^2))/(Ws))*(R2/S)
+K=Tl/((1-S)^2)
+S1=(Ns-Nr2)/Ns
+Tl1=K*((1-S1)^2)
+Vs=sqrt(Tl1*S1*Ws*(((R1+(R2/S1))^2)+((X1+X2)^2))/((3)*(R2)))//Wrongly calculated in textbook
+printf('\n\n The Voltage To be Applied=%0.1f Volts\n\n',Vs)
+//The answer provided in the textbook is wrong