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+clc
+//variable Initialisation
+Vm=400 //Terminal Voltage Of Motor In Volt
+F=50 //Supply Frequency Of Motor
+P=6 //Number Of Pole
+R1=0.2 //Resistance Of Motor in Ohm
+R2=0.2 //Resistance Of Motor in Ohm
+X1=0.5 //Reactance in Ohm
+X2=0.5 //Reactance in Ohm
+Xm=15 //Reactance In Ohm
+S=0.05 //Slip Of Motor
+
+//Solution
+Ns=(120*F)/(P)
+Ws=((2*%pi)/60)*(Ns)
+Vph=Vm/sqrt(3)
+S1=2-S
+I2=(Vph)/sqrt(((R1+(R2/S1))^2)+((X1+X2)^2))
+Im=Vph/Xm
+I1=Im+I2
+Tb=((3*((I2)^2))/(Ws))*(R2/S1)
+printf('\n\n The Primary Current=%0.1f Amp\n\n',I1)
+printf('\n\n The Braking Torque=%0.1f N-m\n\n',Tb)