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+clc
+// Variable Initiallization
+Ea=400 // Voltage Of MOtor In Volt
+Ia1=70 //Line Current In Ampere
+Ia2=90 //Line Current In Ampere
+Ra=0.3 //Armature Resistance In Ohm
+N1=750 //Speed Of Motor In rpm
+N2=300 //Speed Of Motor In rpm
+
+//Solution
+Eb1=Ea-(Ia1*Ra)
+Eb2=(N2/N1)*Eb1
+Rb=-((Eb2-Ea-Ia2*Ra)/Ia2)//Wrongly calculated in book,wrong value of Eb2 is taken
+W1=(2*%pi*N1)/60
+Kt1=Eb1/W1
+T1=Kt1*Ia1
+W2=(2*%pi*N2)/60
+Kt2=Eb2/W2//Wrongly computed in textbook
+T2=Kt2*Ia2//The answer provided in the textbook is wrong
+printf('\n\n External resistance to be added=%0.1f ohm\n\n',Rb)
+printf('\n\n Initial braking torque=%0.1f N-m\n\n',T1)
+printf('\n\n braking torque at 300 rpm=%0.1f N-m\n\n',T2)
+//The answer provided in the textbook is wrong(both)