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+clc
+// Variable Initialization 
+Vm=230//Supply Voltage in Volts
+Ra=0.05//Armature circuit resistance in Ohm
+La=3e-3//Inductance in mH
+N=750//Motor speed in Rpm
+V=220//Rated voltage of motor in Volts
+a=60//firing angle in Degree
+I=175 //motor current in Amp
+f=50 //source Frequency in Hz
+
+//La=2.85 mH
+N2=-400
+a1=120
+P1=atand((2*%pi*f*La)/Ra) // In Degree
+Eb=V-(I*Ra) //back emf in Volts
+w=(2*%pi*N)/60 //Angular Speed in rad/sec
+K=Eb/w
+Cot_P1=1/(tand(P1))
+Eb1=(N2/N)*Eb//Back emf in Volts
+Z1=sqrt((Ra^2)+((2*%pi*f*La)^2)) //Impedance In Ohm
+AA1=(Ra*Vm*1.414)/(K*Z1)
+A1=exp(-%pi*Cot_P1)
+Wmc1=AA1*sind(a1-P1)*((1+A1)/(A1-1))//Critical Speed in rad/Sec
+Wrpm1=(Wmc1*60)/(2*%pi) //speed in rpm
+Eb2=(Wrpm1*Eb)/N
+a2=150
+Va=(2*1.414*Vm)*(cosd(a2))*(1/%pi)
+Ia=(Va-Eb2)/Ra
+T=K*Ia//Torque in N-m
+//As the torque of 400 N-m is greater than T ,hence the opertion is in Continuous conduction mode
+T1=400
+Ia1=T1/K
+Eb3=Va-(Ia1*Ra)
+Ns=(Eb3*N)/Eb
+//As the torque of 400 N-m is less than T ,hence the opertion is in Discontinuous conduction mode
+Z=0.2716
+q=V*1.414/Z
+//nothing is solved in textbook using numericals
+//By Trial and error method beta is calculated
+b=233.240
+
+//Results
+printf('\n\n The motor Speed =%0.1f rpm \n\n',Ns)