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Diffstat (limited to '3776/CH9/EX9.4/Ex9_4.sce')
-rw-r--r-- | 3776/CH9/EX9.4/Ex9_4.sce | 28 |
1 files changed, 28 insertions, 0 deletions
diff --git a/3776/CH9/EX9.4/Ex9_4.sce b/3776/CH9/EX9.4/Ex9_4.sce new file mode 100644 index 000000000..f645233f8 --- /dev/null +++ b/3776/CH9/EX9.4/Ex9_4.sce @@ -0,0 +1,28 @@ +clear +//Given +// +b = 40.0 //mm - The width of the beam crossection +h = 300.0 //mm - The length of the beam crossection +V = 40.0 //KN - The shear stress in teh crossection +M = 10.0 //KN-m - The bending moment on K----K crossection +c = h/2 //mm -The position at which maximum stress occurs on the crossection +I = b*(h**3)/12 //mmm4 - the moment of inertia +//Caliculations + +stress_max_1 = M*c*(10**6)/I //The maximum stress occurs at the end +stress_max_2 = -M*c*(10**6)/I //The maximum stress occurs at the end +y = 140 //mm The point of interest, the distance of element from com +n = y/(c) // The ratio of the distances from nuetral axis to the elements +stress_L_1 = n*stress_max_1 //The normal stress on elements L--L +stress_L_2 = -n*stress_max_1 //The normal stress on elements L--L +x = 10 //mm The length of the element +A = b*x //mm3 The area of the element +y_1 = y+x/2 // the com of element from com of whole system +stress_xy = V*A*y_1*(10**3)/(I*b) //MPa - The shear stress on the element +//stresses acting in plane 30 degrees +o = 60 //degrees - the plane angle +stress_theta = stress_L_1/2 + stress_L_1*(cos((%pi/180)*(o)))/2 - stress_xy*(sin((%pi/180)*(o))) //MPa by direct application of equations +stress_shear = -stress_L_1*(sin((%pi/180)*(o)))/2 - stress_xy*(cos((%pi/180)*(o))) //MPa Shear stress + +printf("\n a)The principle stresses are %0.2f MPa %0.2f MPa",stress_max_1,stress_max_2) +printf("\n b)The stresses on inclines plane %0.2f MPa noraml, %0.2f MPa shear ",stress_theta,stress_shear) |