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+clear
+//Given
+//
+b = 40.0 //mm - The width of the beam crossection
+h = 300.0 //mm - The length of the beam crossection
+V = 40.0 //KN - The shear stress in teh crossection
+M = 10.0 //KN-m - The bending moment on K----K crossection
+c = h/2 //mm -The position at which maximum stress occurs on the crossection
+I = b*(h**3)/12 //mmm4 - the moment of inertia
+//Caliculations
+
+stress_max_1 = M*c*(10**6)/I //The maximum stress occurs at the end
+stress_max_2 = -M*c*(10**6)/I //The maximum stress occurs at the end
+y = 140 //mm The point of interest, the distance of element from com
+n = y/(c) // The ratio of the distances from nuetral axis to the elements
+stress_L_1 = n*stress_max_1 //The normal stress on elements L--L
+stress_L_2 = -n*stress_max_1 //The normal stress on elements L--L
+x = 10 //mm The length of the element
+A = b*x //mm3 The area of the element
+y_1 = y+x/2 // the com of element from com of whole system
+stress_xy = V*A*y_1*(10**3)/(I*b) //MPa - The shear stress on the element
+//stresses acting in plane 30 degrees
+o = 60 //degrees - the plane angle
+stress_theta = stress_L_1/2 + stress_L_1*(cos((%pi/180)*(o)))/2 - stress_xy*(sin((%pi/180)*(o))) //MPa by direct application of equations
+stress_shear = -stress_L_1*(sin((%pi/180)*(o)))/2 - stress_xy*(cos((%pi/180)*(o))) //MPa Shear stress
+
+printf("\n a)The principle stresses are %0.2f MPa %0.2f MPa",stress_max_1,stress_max_2)
+printf("\n b)The stresses on inclines plane %0.2f MPa noraml, %0.2f MPa shear ",stress_theta,stress_shear)