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+clear
+//
+M = 10 //KN.m - The moment applied
+I_max = 23.95*(10**6) //mm4 - I_z The moment of inertia
+I_min = 2.53*(10**6) //mm4 - I_y The moment of inertia
+o = 14.34 // degress the principle axis rotated
+//Coponents of M in Y,Z direction
+M_z = M*(10**6)*cos((%pi/180)*(o))
+M_y = M*(10**6)*sin((%pi/180)*(o))
+//tanb = I_z /I_y *tan14.34
+b = atan((I_max*tan((%pi/180)*(o))/I_min ))
+B = (180/%pi)*(b)
+y_p = 122.9 // mm - principle axis Y cordinate
+z_p = -26.95 //mm - principle axis z cordinate
+stress_B = - M_z*y_p/I_max + M_y*z_p/I_min //MPa - Maximum tensile stress
+y_f = -65.97 // mm - principle axis Y cordinate
+z_f = 41.93 //mm - principle axis z cordinate
+stress_f = - M_z*y_f/I_max + M_y*z_f/I_min //MPa - Maximum compressive stress
+//location of nuetral axis To show these stresses are max and minimum
+//tanB = MzI_z + MzI_yz/MyI_y +M_YI_yz
+I_z = 22.64 *(10**6) //mm4 moment of inertia in Z direction
+I_y = 3.84 *(10**6) //mm4 moment of inertia in Y direction
+I_yz =5.14 *(10**6) //mm4 moment of inertia in YZ direction
+M_y = M //KN.m bending moment in Y dorection
+M_z = M //KN.m bending moment in Y dorection
+B = atan(( M_z*I_yz)/(M_z*I_y )) //(%pi/180)* location on neutral axis
+beta = (180/%pi)*(B)
+printf("\n By sketching the line with angle %0.1f degrees The farthest point associated with B and F",beta)