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Diffstat (limited to '3774/CH9/EX9.15/Ex9_15.sce')
-rw-r--r-- | 3774/CH9/EX9.15/Ex9_15.sce | 131 |
1 files changed, 131 insertions, 0 deletions
diff --git a/3774/CH9/EX9.15/Ex9_15.sce b/3774/CH9/EX9.15/Ex9_15.sce new file mode 100644 index 000000000..26caa5ae5 --- /dev/null +++ b/3774/CH9/EX9.15/Ex9_15.sce @@ -0,0 +1,131 @@ +// exa 9.15 Pg 279 + +clc;clear;close; + +// Given Data +W=100;// kN +lift=260;// mm +pb=15;// N/mm.sq. +mu=0.15;// coefficient of thread friction +mu_c=0.20;// coefficient of collar friction +//Screw +Suts=800;// N/mm.sq. +sigma_ss=340;// N/mm.sq. +ns=4;// factor of safety +//Nut +Sutn=552;// N/mm.sq. +sigma_sn=260;// N/mm.sq. +nn=5;// factor of safety + +sigma_ts=Suts/ns;// N/mm.sq. +sigma_cs=Suts/ns;// N/mm.sq. +tau_s=sigma_ss/ns;// N/mm.sq. +sigma_tn=Sutn/nn;// N/mm.sq. +sigma_cn=Sutn/nn;// N/mm.sq. +tau_n=sigma_sn/nn;// N/mm.sq. + +//sigma_cs=4*W/(%pi*dc**2) +dc=sqrt(4*W*10**3/(%pi*sigma_cs));// mm +printf('\n Screw Diameter-\n Core diameter of screw, dc=%.2f mm. Use dc=33 mm',dc) +dc=33;// mm +p=7;// mm (for normal series square threads) +d=dc+p;//mm +printf('\n outside diameter = %.f mm',d) +dm=dc+p/2;// mm +printf('\n mean diameter = %.1f mm',dm) +t=p/2;// mm +printf('\n thread thickness = %.1f mm',t) + +printf('\n Maximum stresses in screw -') +sigma_c=4*W*1000/%pi/dc**2;// MPa +alfa=atand(p/(%pi*dm));// degree +fi=atand(mu);// degree +Tf=dm*W*10**3/2*tand(alfa+fi);// where TfByW = Tf/W +tau=16*Tf/(%pi*dc**3);// MPa +sigma12=(1/2)*(sigma_c+sqrt(sigma_c**2+4*tau**2));// MPa +printf('\n Maximum tensile stress = %.1f N/mm.sq. < %.f N/mm.sq.. Hence design is safe.',sigma12,sigma_ts) +tau_max=sqrt((sigma_c/2)**2+tau**2);// MPa +printf('\n Maximum shear stress = %.2f N/mm.sq. < %.f N/mm.sq.. Hence design is safe.',tau_max,tau_s) + +printf('\n Height of nut-') +n=W*10**3/(%pi/4)/pb/(d**2-dc**2);// no. of threads +n= ceil(n);// no. of threads (rounding) +h=n*p;// mm +printf('\n h=%.f mm. Use 120 mm.',h) +h=120;// mm + +printf('\n Check for stress in screw and nut') +tau_screw=W*10**3/(%pi*n*dc*t);// MPa +printf('\n shear stress in screw = %.2f MPa < %.f MPa',tau_screw,tau_s) +tau_nut=W*10**3/(%pi*n*d*t);// MPa +printf('\n shear stress in nut = %.2f MPa < %.f MPa',tau_nut,tau_n) +printf('\n These are within permissible limits. Hence design is safe.') + +printf('\n Nut collar size-') +// %pi/4*(D1**2-d**2)*sigma_tn=W +D1=sqrt(W*10**3/(%pi/4)/sigma_tn+d**2);// mm +printf('\n Inside diameter of collar = %.2f mm. Use D1=55 mm',D1) +D1=55;//mm (adopted for design) +// %pi/4*(D2**2-D1**2)*sigma_cn=W +D2=sqrt(W*10**3/(%pi/4)/sigma_cn+D1**2);// mm +printf('\n Outside diameter of collar = %.2f mm. Use D2=70 mm',D2) +D2=70;//mm (adopted for design) + +// %pi*D1*tc*tau_n=W +tc=W*10**3/(%pi*D1*tau_n);// mm +printf('\n thickness of nut = %.f mm. Use tc=15 mm.',tc) +tc=15;// mm (adopted for design) + +printf('\n Head Dimensions-') +D3=1.75*d;// mm +printf('\n Diameter of head on top of screw = %.2f mm.',D3) +D4=D3/4;// mm +printf('\n pin diameter in the cup = %.1f mm. Use 20 mm.',D4) +D4=20;// mm (adopted for design) + +printf('\n Torque required between cup and head-') +Tc=mu_c*W*10**3/3*((D3**3-D4**3)/(D3**2-D4**2));// N.mm +printf('\n Tc=%.f N.mm (acc. to uniform pressure theory)',Tc) +T=Tf+Tc;// N.mm +printf('\n Total Torque, T=%.f N.mm',T) + +F=300;// N (as a normal person can apply 100-300 N) +l=T/F;//mm +printf('\n length of lever = %.f mm or %.2f m',l,l/1000) + +M=F*l;// N.mm +sigma_b=100;// N/mm.sq. (assumed) +dl=(32*M/%pi/sigma_b)**(1/3);// mm +printf('\n Diameter of lever, dl=%.1f mm. Use dl=45 mm.',dl) +dl=45;// mm (adopted for design) + +H=2*dl;// mm +printf('\n Height of head, H=%.f mm',H) + +printf('\n Check for screw in buckling-') +L=lift+0.5*h;// mm +K=dc/4;// mm +C=0.25;// spring index +sigma_y=200;// MPa +Ac=%pi/4*dc**2;//mm.sq. +Wcr=Ac*sigma_y*(1-(sigma_y/4/C/%pi**2/(200*10**3))*(L/K)**2)/1000;// kN +printf('\n Buckling or critical load for screw, Wcr = %.f kN > 100kN',Wcr) + +To=W*10**3*dm/2*tand(alfa);// N.mm +eta=To/T*100;// % +printf('\n Efficiency of screw = %.2f %%',eta) + +printf('\n Body dimensions-') +D5=1.5*D2;// mm +t2=2*tc;// mm +t3=0.25*d;//mm +D6=2.25*D2;// mm +printf('\n Diameter of body at top, D5 = %.f mm', D5) +printf('\n Thickness of base, t2 = %.f mm', t2) +printf('\n Thickness of body, t3 = %.f mm', t3) +printf('\n Inside diameter of bottom, D6 = %.1f mm. Use D6=160 mm.', D6) +D6=160;// mm (adopted for design) +D7=1.75*D6;// mm +hb=lift+h+100;// mm +printf('\n Outside diameter at the bottom, D7 = %.2f mm.', D7) +printf('\n Height of body = %.f mm.',hb) |