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Diffstat (limited to '3772/CH4/EX4.13/Ex4_13.sce')
-rw-r--r-- | 3772/CH4/EX4.13/Ex4_13.sce | 110 |
1 files changed, 110 insertions, 0 deletions
diff --git a/3772/CH4/EX4.13/Ex4_13.sce b/3772/CH4/EX4.13/Ex4_13.sce new file mode 100644 index 000000000..eea654f0b --- /dev/null +++ b/3772/CH4/EX4.13/Ex4_13.sce @@ -0,0 +1,110 @@ +// Problem no 4.4.13,Page No.103 + +clc;clear; +close; +F_E=20 //KN //Pt Load at E +F_C=30 //KN //Pt Load at C +F_B=60 //KN //Pt Load at B +L_AB=1.5;L_BC=1.5;L_CD=1.5 //m //Length of AB,BC,CD respectively +L_DE=2.5 //m //Length od DE +L_AD=4.5 //m //Length of AD +L=7 //m //Length of beam +w=30 //KN/m + +//Calculations + +//LEt R_A and R_D be the reactions at A and D +//R_A+R_D=245 + +//Taking moment at A +//M_A=0=-R_D*(L_BC+L_AB+L_CD)+F_E*L+w*L_Ad**2*2**-1+F_C*(L_AB+L_BC)+F_B*L_AB +R_D=-(-(F_E*L)-(w*L_AD**2*2**-1)-F_C*(L_AB+L_BC)-F_B*L_AB)*(L_BC+L_AB+L_CD)**-1 +R_A=245-R_D + +//Shear Force Calculations + +//Shear Force at C +V_E1=0 +V_E2=-F_E + +//Shear Force at D +V_D1=V_E2 +V_D2=V_E2+R_D + +//Shear Force at C +V_C1=V_D2 +V_C2=V_D2-F_C-w*L_CD + +//Shear Force at B +V_B1=V_C2 +V_B2=-F_E+R_D-F_C-w*(L_BC+L_CD)-F_B + +//Shear Force at A +V_A=-F_E-F_C-F_B-w*L_AD+R_D + +//Pt of contraflexure +//Let F be the pt and EF=x +//V_F=-F_E-F_C+R_D-w*L_FE+w*L_DE +L_FE=-(F_E+F_C-R_D-w*L_DE)*w**-1 +L_FD=L_FE-L_DE +L_FC=L_FE-L_CD-L_DE + +//Bending Moment Calculations + +//Bending Moment at E +M_E=0 + +//Bending Moment at D +M_D=-F_E*L_DE + +//Bending Moment at C +M_C=-F_E*(L_CD+L_DE)+R_D*L_CD-w*L_CD**2*2**-1 + +//Bending Moment at F +M_F=-w*L_FD**2*2**-1-F_C*L_FC+R_D*L_FD-F_E*L_FE + +//Bending Moment at B +M_B=-F_E*(L_DE+L_CD+L_BC)-F_C*L_BC+R_D*(L_CD+L_BC)-w*(L_BC+L_CD)**2*2**-1 + +//Bending Moment at A +M_A=-F_E*L+R_D*(L_AD)-F_C*(L_BC+L_AB)-F_B*L_AB-w*(L_AD)**2*2**-1 + +//Bending Moment at F +M_F=-F_E*L_FE+R_D*L_FD-F_C*L_FC-w*L_FD**2*2**-1 + +//Pt of contraflexure +//Let G be the pt and GE=y +//M_G=-F_E*L_GE+R_D*(L_GE-L_DE)-F_C*(L_GE-L_DE)**2*2**-1 +//After substituting values and further simplifying we get +//y**2-12.9+29.35=0 +a=1 +b=-12.9 +c=29.35 + +X=b**2-4*a*c + +y1=(-b+X**0.5)*(2*a)**-1 +y2=(-b-X**0.5)*(2*a)**-1 + +//Result +printf("The Shear Force and Bending Moment Diagrams are the results") + +//Plotting the Shear Force Diagram +subplot(2,1,1) +X1=[0,0,L_DE,L_DE,L_DE+L_CD,L_DE+L_CD,L_DE+L_CD+L_BC,L_DE+L_CD+L_BC,L_DE+L_CD+L_BC+L_AB,L_DE+L_CD+L_BC+L_AB] +Y1=[V_E1,V_E2,V_D1,V_D2,V_C1,V_C2,V_B1,V_B2,V_A,0] +Z1=[0,0,0,0,0,0,0,0,0,0] +plot(X1,Y1,X1,Z1) +xlabel("Length x in m") +ylabel("Shear Force in kN") +title("the Shear Force Diagram") + +//Plotting the Bending Moment Diagram +subplot(2,1,2) +X2=[0,L_DE,L_DE+L_CD,L_DE+L_CD+L_FC,L_DE+L_CD+L_BC,L_DE+L_CD+L_BC+L_AB] +Y2=[M_E,M_D,M_C,M_F,M_B,M_A] +Z2=[0,0,0,0,0,0] +plot(X2,Y2,X2,Z2) +xlabel("Length in m") +ylabel("Bending Moment in kN.m") +title("the Bending Moment Diagram") |