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+// Problem 3.7,Page no.57
+
+
+clc;clear;
+close;
+
+//from F.B.D,we get
+P_1=50 //KN
+P_2=20 //KN
+P_3=40 //KN
+
+d=0.02 //mm //Diameter of steel bar
+L_1=0.4 //mm
+L_2=0.3 //mm
+L_3=0.2 //mm
+E=210*10**9 //N
+
+//After simplifying Area,we get
+A=%pi*10**-4 //m**2 //Area of cross section
+
+//Calculations
+
+sigma_AB=P_1*1000*A //N/m**2
+sigma_BA=P_2*1000*A //N/m**2
+sigma_CD=P_3*1000*A //N/m**2
+dell_L=((P_1*L_1+P_2*L_2+P_3*L_3)*(A*E)**-1)*10**6 //mm
+
+//Result
+printf("Total Elongation of Steel bar is %.3f mm",dell_L)