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+// Problem no 10.7,Page No.261
+clc;
+clear;
+close;
+
+
+//Calculations
+
+theta=atan(1*2**-1)*(180*%pi**-1) //Radian
+
+//Taking moment about A
+R_EH=10*8*4**-1
+
+//Horizontal component of reaction at A
+R_AH=20 //KN
+
+//Applying the summation of horizontal  forces  we get
+F_AB=20*cos(theta*%pi*180**-1)**-1
+
+//Applying the summation of vertical forces  we get
+R_AV=10*5**0.5*sin(theta*%pi*180**-1)
+
+//Vertical Reaction at E
+R_EV=0
+
+//Joint C
+
+//Applying the summation of vertical forces  we get
+F_DC=10*sin(theta*%pi*180**-1)**-1
+
+//Applying the summation of horizontal  forces  we get
+F_CB=F_DC*cos(theta*%pi*180**-1)
+
+//Joint D
+
+//Applying the summation of vertical forces  we get
+F_DB=F_DC*sin(theta*%pi*180**-1)
+
+//Applying the summation of horizontal  forces  we get
+F_DE=F_DC*cos(theta*%pi*180**-1)
+
+//Joint E
+
+//Applying the summation of vertical forces  we get
+F_EB=R_EV*sin(theta*%pi*180**-1)
+
+//Result
+printf("Forces in Each members are as follows:F_AB %.2f",F_AB);printf(" KN(Tensile)")
+printf("\n                                      :F_DC %.2f",F_DC);printf(" KN(compression)")
+printf("\n                                      :F_CB %.2f",F_CB);printf(" KN(Tensile)")
+printf("\n                                      :F_DB %.2f",F_DB);printf(" KN(Tensile)")
+printf("\n                                      :F_DE %.2f",F_DE);printf(" KN(compression)")
+printf("\n                                      :F_EB %.2f",F_EB);printf(" KN")