diff options
Diffstat (limited to '3772/CH10/EX10.4/Ex10_4.sce')
| -rw-r--r-- | 3772/CH10/EX10.4/Ex10_4.sce | 42 |
1 files changed, 42 insertions, 0 deletions
diff --git a/3772/CH10/EX10.4/Ex10_4.sce b/3772/CH10/EX10.4/Ex10_4.sce new file mode 100644 index 000000000..a07330b75 --- /dev/null +++ b/3772/CH10/EX10.4/Ex10_4.sce @@ -0,0 +1,42 @@ +// Problem no 10.4,Page No.253 + +clc;clear; +close; + +//JOint D + +//Applying the summation of vertical forces we get +F_1=6*sin(30*%pi*180**-1)**-1 + +//Applying the summation of horizontal forces we get +F_5=F_1*cos(30*%pi*180**-1) + +//Joint C + +//Resolving forces perpendicular to plane +F_6=10*cos(30*%pi*180**-1) + +//Resolving forces parallel to plane +F_2=F_1+10*cos(60*%pi*180**-1) + +//Joint E + +//Applying the summation of vertical forces we get +F_7=(8+F_6*sin(60*%pi*180**-1))*(sin(60*%pi*180**-1))**-1 +F_4=F_5+F_6*cos(60*%pi*180**-1)+F_7*cos(60*180**-1*%pi) + +//Resolving forces perpendicular to plane +F_3=F_7*sin(60*%pi*180**-1) + +//Resolving forces parallel to plane +F_8=F_2+F_7*cos(30*%pi*180**-1) + +//Result +printf("Forces in Each members are as follows:F_1 %.2f",F_1);printf(" KN(Tension)") +printf("\n :F_5 %.2f",F_5);printf(" KN(compression)") +printf("\n :F_6 %.2f",F_6);printf(" KN(compression)") +printf("\n :F_2 %.2f",F_2);printf(" KN(Tension)") +printf("\n :F_7 %.2f",F_7);printf(" KN(Tension)") +printf("\n :F_4 %.2f",F_4);printf(" KN(compression)") +printf("\n :F_3 %.2f",F_3);printf(" KN(compression)") +printf("\n :F_8 %.2f",F_8);printf(" KN(Tension)") |