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+clear
+//Given
+m=1.67*10**-27
+v=4*10**5
+a=60
+q=1.6*10**-19
+B=0.3
+
+//Calculation
+//
+r=(m*v*sin(a*3.14/180.0))/q*B
+P=v*cos(a*3.14/180.0)*((2*%pi*m)/(q*B))
+
+//Result
+printf("\n (i) Radius of the helical path is %0.1f cm",r*10**3)
+printf("\n (ii) Pitch of helix is %0.2f cm",P*10**2)