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+disp("Example 4.2")
+disp("Given Moment value = 140kNm")
+disp("Grade of Steel = Fe415","Grade of Concrete = M20","D=600mm","d=550mm","b=300mm","Bars used = 4 - 25 dia")
+disp("Transformed Section Properties")
+disp("Modula ratio m = 13.33 for M20")
+disp("Transformed Steel Area = m*Ast")
+m=13.33
+d=550
+b=300
+D=600
+M=140
+Ast=%pi*25*25*4/4 // Value of Ast is varying a bit b'cos of value of pi considered
+mAst=m*Ast
+disp(mAst) // and hence value of mAst is varying a little
+disp("Equating Moments")
+disp("b*k*d*d/2 = mAst*(d-k*d)")
+b1=(2*mAst/b)
+c=(-mAst*2*d/b)
+a=1
+kd1=((-b1+sqrt((b1*b1)-(4*a*c)))/(2*a))
+kd2=((-b1-sqrt((b1*b1)-(4*a*c)))/(2*a))
+disp("mm",kd1,"therefore, kd=")
+k=kd1/d
+disp("mm",k,"k=")
+disp("Lever arm, jd = d(1-k/3)")
+j=(1-k/3)*d
+disp("mm",j,"jd=")
+
+//Calculating Stresses
+
+disp("Maximum Concrete Stresses")
+disp("Taking moments about the tension steel centroid,")
+disp("M=0.5*fc*b*kd*jd")
+fc=((140*10^6)/(0.5*300*234.6*471.8))
+disp("in MPa",fc,"fc=")
+disp("Tensile Stress in Steel")
+disp("Taking moments about the line of action of C")
+fst=((M*10^6)/(Ast*j))
+disp("MPa",fst,"fst=")
+