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diff --git a/3761/CH4/EX4.12/Ex4_12.sce b/3761/CH4/EX4.12/Ex4_12.sce
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+disp("Example 4.12")
+disp("fck=20MPa","fy=Fe250","Ast=3695mm^2","d=520mm","bw=250mm","Df=100mm","bf=850mm","Given:")
+bf=850
+Df=100
+bw=250
+d=520
+Ast=3695
+fy=250
+fck=20
+Es=2*10^5
+xumaxd=0.0035/(0.0055+0.87*(fy/Es))
+xumax=xumaxd*d
+disp("First assuming xu</Df and xu</xu,max and considering force equilibrium")
+disp("Cu=Tu=0.362*fck*bf*xu=0.87*fy*Ast")
+disp("Therefore,xu=")
+xu=(0.87*fy*Ast)/(0.362*bf*xu*fck)
+disp(xu,"mm")
+disp("Since, xu>Df, the value is incorrect ")
+
+disp("Asxu>Df, the compression in web is given by: Cuw=0.362*fck*bw*xu")
+Cuw=0.362*fck*bw
+disp("*xu N",Cuw)
+disp("Assuming xu>/7/3*Df = 233.3, the commpression in the flange is given by: Cuf=0.447*fck*(bf-bw)*Df")
+Cuf=0.447*fck*(bf-bw)*Df
+disp("Cuf=")
+disp("N",Cuf)
+disp("Also assuming xu</xu,max = 276.1mm fst= 0.87*fy, and Tu=0.87*fy*Ast")
+Tu=0.87*fy*Ast
+disp("Tu=")
+disp("N",Tu)
+disp("Aplying the equilibrium conditions (Cuw+Cuf=Tu")
+xu=(Tu-Cuf)/Cuw
+disp("Since, xu<7/3*Df, hence this value of xu is also not correct")
+disp("As Df<xu<7/3*Df, the depth yf</Df of the equivalent concrete stress block is obtained as: yf=0.15*xu+0.65*Df = (0.15*xu+65)mm")
+disp("Cuf=Cuf*(yf/Df)= (804.6*xu+348660)N")
+disp("Cuw+Cuf=Tu")
+xu1=(Tu-(Cuf*(65/100)))/(Cuw+(Cuf*0.15/100))
+disp("xu=")
+disp("mm",xu1)
+disp("As, xu<xu,max; Hence the assumption fst=0.87*fy is OK")
+yf=(0.15*xu1)+65
+disp("mm",yf,"yf=")
+disp("Taking moments of Cuw and Cuf about the centroid of tension steel, MuR= Cuw*(d-0.416*xu)+Cuf*(d-yf/2)")
+Cuf=804.6*xu1+348660
+MuR=(Cuw*xu1*(d-0.416*xu1)+(Cuf*(d-yf/2)))/10^6
+disp("kNm",MuR,"MuR=")
+
+
+
+