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+clc;
+P=10;
+f=50;
+Pm=48000;
+pf=0.8;
+f21=120; //min frequency range
+f22=300; //max frequency range
+Ns=(120*f)/P;
+
+//for f2=300
+Nr1=((120*f21)/P)-Ns;
+//for f2=600
+Nr2=((120*f22)/P)-Ns;
+mprintf('Thus the dc motor changes speed from %f to %f rpm \n',Nr1,Nr2)
+
+//for part b and c
+s1=(Nr1+Ns)/Ns;
+s2=(Nr2+Ns)/Ns;
+Pr=Pm/pf;
+Pr1=Pr/s1;
+Pr2=Pr/s2;
+R1=(s1-1)*Pr1*pf;
+R2=(s2-1)*Pr2*pf;
+T1=(R1*60)/(2*%pi*Nr1);
+T2=(R2*60)/(2*%pi*Nr2);
+// stator should be able to handle higher KVA
+mprintf('KVA rating of induction motor stator is %f KVA\n',Pr1/1000)
+mprintf('DC motor rating is %f KW \n Maximum torque output from DC motor is %f Nm \n',R2/1000,T1);
+
+//for part d
+//When speed is limited to 2700 rpm
+P1=((120*f22)-(120*f))/2700;
+P1=ceil(P1);
+mprintf('Number of Poles is %d \n',P1);
+
+//for part e
+Nr11=((f22*120)/P1)-((120*f)/P1);
+Nr22=((f21*120)/P1)-((120*f)/P1);
+mprintf('Thus the new speed range of dc motor is from %f to %f rpm \n',Nr22,Nr11);
+
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