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diff --git a/3760/CH4/EX4.24/Ex4_24.sce b/3760/CH4/EX4.24/Ex4_24.sce
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+clc;
+//magnetization curve at 1200 rpm
+If=[0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8];//field current in rpm
+Ea=[6 53 106 160 209 241 258 272 282 288];//induced voltage in armature
+plot(If,Ea);xlabel('If');ylabel('Ea');//magnetization curve at 1200 rpm
+Pout=10000;//genertor output in watts
+Vt=230;//Terminal Voltage
+Ra=0.5;//armature resistance with brushes
+Ns=1000;//turns of shunt winding
+Nf=4;//turns of field winding
+Z=1000;//No of conductors
+
+//PART (A)
+//At rated output current the speed is 1150 rpm & shunt field current is 1 A
+If_=1;//field current at rated o/p current
+Il=Pout/Vt;//rated output current
+Ia=Il+If;//armature current at rated load
+Is=Ia;//for long shunt compound generator the series field current is equal to armature current
+//Since the compound geenerator is cumulatively compounded ,the total pole per m.m.f. is (Nf*If+Ns*Is)ampere turns
+//Thus the equivalent shunt field current is given by 1/Nf*(Nf*If+Ns*Is)=1+(4*44.5/1000)=1.18 A. The generated emf for this field currenr from the magnetization curve is 257 volts.
+//For speed of 1150 rpm the generated emf is-
+Ea_=257*(1150/1200);
+Vt_=Ea_-Ia*Ra;//terminal voltage
+
+//PART(B)
+Eg=Vt+Ia*Ra;//generated emf in the armature at 1150 rpm
+//By using the magnetization curve, the generated emf at 1200 rpm will be 252.25*(1200/1500)=263.3 volts.
+//From the open circuit characteristics, the field current corresponding to 263.3 volts is 1.26 A.
+MMFt=1.26*1000;//Total MMF
+//Total MMF must be produced by the combined action of shunt & series windings.
+//1.26*1000=1.00*1000+Ns*(44.5);
+Ns_=(0.26*1000)/44.5;//series field turns
+printf('The number of series field turns should be %f.',round(Ns_));