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+clc;
+k1=1000; // Rated KVA of transformer1
+k2=500; // Rated KVA of transformer2
+ze1=0.02+%i*0.06; // p u leakage impedance of transformer 1
+ze2=0.025+%i*0.08; // p u leakage impedance of transformer 2
+zb=1000; // base impedance
+Z1=(zb/k1)*ze1; // impedance of transformer 1
+Z2=(zb/k2)*ze2; // impedance of transformer 2
+zt=Z1+Z2; // total impedance
+S=k1*(abs(zt)/abs(Z2)); // since ze1<ze2 transformer 1 reaches its rated KVA threrfore load shared by transformer 2 is given by
+l2=S-k1; // load shared by transformer 2
+printf('Largest KVA load that can be loaded on parallel combination of transformer is given by %f KVA',S);
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