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+//Fluid System By Shiv Kumar
+//Chapter 6 - Kaplan and Propeller Turbines
+//Example 6.1
+//To Find (a)Discharge  (b)Diameter of Hub And Diameter of Runner (c)Speed
+
+    clc
+     clear
+     
+//Given:
+   P=37;   //Shaft Power, MW
+   H=22;   //Head, m
+   eta_0=92/100;  //Overall Efficiency
+   dbyD=1/3;   //Ratio of Diameters of Hub and Runner
+   Kf=0.6;     //Flow Ratio
+   Ku=2;       //Speed Ratio
+//Data Required:
+   rho=1000;   //Density of Water, Kg/m^3
+   g=9.81;     //Acceleration due to gravity, m/s^2
+
+//Computations
+
+  //(a)Discharge, Q
+     Q=P*10^6/(rho*g*H*eta_0);   //m^3/s
+
+  //(b)Diameter of Hub(d) And Diameter of Runner(D)
+      d=sqrt(Q/((%pi/4)*Kf*sqrt(2*g*H)*(dbyD^-2-1)));   //m
+      D=d/dbyD;  //m
+  
+  //(c) Speed,N
+     N=Ku*60*sqrt(2*g*H)/(%pi*D);  // rpm
+
+//Results
+  printf("(a)Discharge, Q=%.2f m^3/s \n",Q)   //The answer vary due to round off error
+  printf(" (b)Diameter of Hub, d=%.2f m \n",d)    
+  printf("   Diameter of Runner, D=%.2f m \n",D)   //The answer vary due to round off error
+  printf(" (c)Speed, N=%.2f rpm \n",N)   //The answer vary due to round off error