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+//Fluid system - By - Shiv Kumar
+//Chapter 4 - Pelton Turbine (Impulse Turbine)
+//Example 4.7
+ clc
+ clear
+
+//Given Data:-
+ H_G=500; //Gross Head, m
+ h_f=(1/3)*H_G; //Head lost in friction in penstock, m
+ Q=2; //Discharge, m^3/s
+ AoD=165; //Angle of Deflection of Jet, degrees
+ Ku=0.45; //Speed ratio
+ Cv=1;
+
+//Data Used:-
+ rho=1000; //Density of water, kg/m^3
+ g=9.81; //Acceleration due to gravity, m/s^2
+
+//Computations:-
+ H=H_G-h_f; //Working Head, m
+ Vi=Cv*sqrt(2*g*H); //m/s
+ Vwi=Vi;
+ u=Ku*sqrt(2*g*H); //m/s
+ ui=u;
+ uo=u;
+ Vri=Vi-u; //m/s
+ Vro=Vri;
+ beta_o=180-AoD; //degrees
+ Vrwo=Vro*cosd(beta_o); //m/s
+ Vwo=Vrwo-uo; //m/s
+ P=rho*Q*(Vwi+Vwo)*u/1000; //power given by water to runner, kW
+ eta_H=2*(Vwi+Vwo)*u/Vi^2*100; //Hydraulic efficiency, In percentage
+
+//Results:-
+ printf("Power given by water to the runner=%.2f kW \n", P) //The answer vary due to round off error
+ printf("Hydraulic efficiency, eta_H=%.2f percent", eta_H) //The answer vary due to round off error
+
+
+