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+//Fluid Systems - By - Shiv Kumar
+//Chapter 4 - Pelton Turbine (Impulse Turbine)
+//Example 4.16
+  
+      clc
+       clear
+
+//Given Data:-
+       P=4900;        //Shaft Power, kW
+      P_mr=100;       //Power absorbed in mechanical resistance,  kW
+      eta_H=92/100;        //Hydraulic Efficiency
+      P_n=415;         //Power lost in Nozzle, kW 
+
+
+ //Computations:-
+           P_rd=P+P_mr;         //Power Devrloped by Runner, kW
+           P_rs=P_rd/eta_H;      //Power Supplied to Runner, kW
+           P_an=P_n+P_rs;       //Power Available at base of Nozzle, kW
+           eta_o=P/P_an*100;       //Overall Efficiency in Percentage       
+
+//Results:-
+        printf("(a)Power Available at the Base of Nozzle=%.3f kW\n",P_an)       //The answer vary due to round off error
+        printf("(b)Overall Efficiency, eta_o=%.2f Percent\n",eta_o)
+
+
+