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+//Fluid system - By - Shiv Kumar
+//Chapter 2 - Impact of Jet
+//Example 2.11
+ clc
+ clear
+//Given Data:-
+ //(a)
+ V=60; //Velocity of the Jet, m/s
+ theta=30; //Angle of Outlet, degrees
+ //(b)
+ u=25; //Velocity of vane, m/s
+
+
+//Data Used:-
+ g=9.81; //Acceleration due to gravity, m/s^2
+
+//Computations:-
+ //(a)
+ Fx=(V/g)*(1+cosd(theta)); //Force exerted by Unit weight of water in direction of Jet, N/N of Water
+ Fy=V*sind(theta)/g; //Force exerted by Unit weight of water in direction perpendicular to direction of Jet, N/N of Water
+ F_R=sqrt(Fx^2+Fy^2); //Resultant for per unit weight of water, N/N of Water
+ phi=atand(Fy/Fx); //Angle made by resultant with X-axis, degrees
+
+//Results(a):-
+ printf("(a)\nForce exerted by Unit weight of water in direction of Jet, Fx=%.2f N/N of Water \n", Fx)
+ printf("Force exerted by Unit weight of water in direction perpendicular to direction of Jet, Fy=%.2f N/N of water \n", Fy) //The answer vary due to round off error
+ printf("Resulatant Force, F_R=%.2f N/N of Water at angle, phi=%.2f degrees \n\n", F_R, phi) //The answer vary due to round off error
+ //(b)
+ Fx=(V-u)*(1+cosd(theta))/g; //Force exerted by Unit weight of water in direction of Jet, N/N of Water
+ Fy=(V-u)*sind(theta)/g; //Force exerted by Unit weight of water in direction perpendicular to direction of Jet, N/N of Water
+ F_R=sqrt(Fx^2+Fy^2); //Resultant force per unit weight of water, N/N of Water
+ phi=atand(Fy/Fx); //Angle made by resultant with X-axis, degrees
+ W=Fx*u; //N-m/s/N of Water
+ P=Fx*u/1000; //Power developed per unit weight of water, KW/N of Water
+ //Result(b)
+ printf("(b)\nForce exerted by Unit weight of water in direction of Jet, Fx=%.2f N/N of Water \n", Fx) //The answer vary due to round off error
+ printf("Force exerted by Unit weight of water in direction perpendicular to direction of Jet, Fy=%.2f N/N of water \n", Fy)
+ printf("Resulatant Force, F_R=%.2f N/N of Water at angle, phi=%.2f degrees \n\n", F_R, phi) //The answer vary due to round off error
+ printf("Work done per unit weight of water=%.2f N-m/s/N of Water \n", W) //The answer vary due to round off error
+ printf("Power developed per unit weight of water=%.4f KW/N of Water", P) //The answer vary due to round off error