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+//Fluid Systems - By Shiv Kumar
+//Chapter 17- Dimensional and Model Analysis
+//Example 17.18
+//To Find the Velocity and Rate of Flow in the Model.
+
+ clc
+ clear
+
+//Given:-
+ //For Model ( Working Fluid is Water),
+ Dm=150; //Diameter of Pipe, mm
+ mu_m=0.01; //Viscosity of Water, Poise
+
+ //For Prototype ( Working Fluid is Oil),
+ Dp=1.5; //Diameter, m
+ Sp=0.9; //Specific Gravity of Oil
+ mu_p=3*10^-2; //Viscosity of Oil, Poise
+ Qp=3000; //Discharge of Oil, Litres/sec
+
+//Data Required:-
+ rho_m=1000; //Density of Water, Kg/m^3
+
+
+//Computations:-
+ Dm=Dm/1000; //m
+ Qp=Qp/1000; //m^3/s
+ Ap=(%pi/4)*Dp^2; //m^2
+ Am= (%pi/4)*Dm^2 ; //m^2
+ Vp=Qp/Ap; //m/s
+ rho_p=Sp*rho_m; //Kg/m^3
+
+ //From Reynold's Law of Similarity,
+ Vm=Vp*(Dp/Dm)*(mu_m/mu_p)*(rho_p/rho_m); //Velocity of Water in Model, m/s
+ Qm=Am*Vm*1000; //Rate of Flow in Model, Litres/sec
+
+//Results:-
+ printf("The Velocity in the Model, Vm=%.3f m/s\n",Vm) //The Answer Vary due to Round off Error
+ printf("The Rate of Flow in the Model, Qm=%.2f Litres/sec\n",Qm) //The Answer Vary due to Round off Error
+
+