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diff --git a/3751/CH16/EX16.9/Ex16_9.sce b/3751/CH16/EX16.9/Ex16_9.sce new file mode 100644 index 000000000..b1562f85b --- /dev/null +++ b/3751/CH16/EX16.9/Ex16_9.sce @@ -0,0 +1,34 @@ +//Fluid Systems - By Shiv Kumar +//Chapter 16- Hydraulic Power and Its Transmissions +//Example 16.9 +//To Deternmine the Diameter of the ram. + clc + clear + +//Given Data:- + d=125; //Diameter of Pipe, mm + l=2; //Lenght of Pipe, km + P=35; //Power Transmitted, kW + W=1250; //Load on ram, kN + loss_per=3; //Percentage of Power Loss due to friction + f_dash=0.04; //Pipe Friction Factor + +//Data Used:- + rho=1000; //Density of Water, kg/m^3 + g=9.81; //Acceleration due to gravity, m/s^2 + +//Computations:- + Delta_P=loss_per/100*P*1000; //Power Loss due to friction , W + //By Darcy's Formula, + hf_by_V2=f_dash*(l*1000)/(2*g*d/1000); //hf/V^2 + + QbyV=(%pi/4)*(d/1000)^2; //Q/V + V=( Delta_P/(rho*g*QbyV*hf_by_V2))^(1/3); //m/s + Q=QbyV*V; //m^3/s + p=P*1000/Q; //N/m^2 + D=sqrt(W*1000/(p*%pi/4))*1000; //mm + +//Result:- + printf("The Diameter of ram, D=%.2f mm",D) //The answer vary due to round off error + + |