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Diffstat (limited to '3751/CH16/EX16.14/Ex16_14.sce')
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diff --git a/3751/CH16/EX16.14/Ex16_14.sce b/3751/CH16/EX16.14/Ex16_14.sce new file mode 100644 index 000000000..b4699d3b0 --- /dev/null +++ b/3751/CH16/EX16.14/Ex16_14.sce @@ -0,0 +1,45 @@ +//Fluid Systems - By Shiv Kumar +//Chapter 16- Hydraulic Power and Its Transmissions +//Example 16.14 +//To Find (i)The Force applied in Plunger (ii) The Number of Strokes performed by Plunger (iii) Work done by the Press Ram and (iv) Power required to drive the Plunger. + + clc + clear + +//Given Data:- + D=180; //Diameter of ram, mm + d=36; //Diameter of Plunger, mm + W=7 ; //Weight exerted by Press ram, kN + L=300; //Stroke Length of Plunger, mm + l=0.9; //Distance moved by ram, m + t=15; //Time, minutes + +//Computations:- + D=D/1000; //m + A=(%pi/4)*D^2; //m^2 + d=d/1000; //m + a= (%pi/4)*d^2; //m^2 + W=W*1000; //N + L=L/1000; //m + t=t*60; //seconds(s) + + // (i)The Force applied in Plunger, F1 + F1=(a/A)*W; //N + + //(ii) The Number of Strokes performed by Plunger, n + n=(A/a)*(l/L); + + // (iii) Work done by the Press Ram + Work=W*l; //N-m + + // (iv) Power required to drive the Plunger, P + P=Work/t; //W + + +//Results:- + printf(" (i) The Force applied in Plunger, F1=%.2f N \n",F1) //The answer vary due to round off error + printf(" (ii) The Number of Strokes performed by Plunger, n =%.f \n",n) + printf(" (iii) Work done by the Press Ram =%.f N.m \n",Work) + printf(" (iv) Power required to drive the Plunger, P =%.f W \n",P) + + |