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diff --git a/3751/CH16/EX16.10/Ex16_10.sce b/3751/CH16/EX16.10/Ex16_10.sce new file mode 100644 index 000000000..5539e21dc --- /dev/null +++ b/3751/CH16/EX16.10/Ex16_10.sce @@ -0,0 +1,33 @@ +//Fluid Systems - By Shiv Kumar +//Chapter 16- Hydraulic Power and Its Transmissions +//Example 16.10 +//To Find (i)The Weight of Loaded Cylinder and energy stored by the Cylinder (ii)Ther Power supplied by the Accumulator (iii)The Diameter of ram of an ordinary Accumulator. + clc + clear + +//Given Data:- + D=180; // mm + d=150; //mm + L=1.25; //Stroke length, m + p=100; //Pressure of Water, bar + +//Computations:- + D=D/1000; //m + d=d/1000; //m + p=p*10^5; //N/m^2 + + A=(%pi/4)*(D^2-d^2); //Annular area of Ram, m^2 + //(i) + W=p*A/1000; //Weight of Loaded Cylinder, kN + Energy=W*L; //Energy stored in the Accumulator, kNm + //(ii) + t=90; //Time taken by ram to complete the stroke, seconds + P=W*L/t; //kW + //(iii) + D=(W*1000/(p*%pi/4))^(1/2)*1000; //mm + +//Results:- + printf("(i)Weight of Loaded Cylinder, W=%.2f kN\n",W) //The answer vary due to round off error + printf(" Energy stored in the Accumulator=%.3f kNm\n",Energy) //The answer vary due to round off error + printf("(ii)Power Supplied by the Accumulator=%.3f kW\n",P) //The answer vary due to round off error + printf("(iii)Ram Diameter (In case of Ordinary Accumulator) = %.2f mm\n",D) //The answer vary due to round off error |