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+//Fluid Systems - By - Shiv Kumar
+//Chapter 11- Centrifugal Pumps
+//Example 11.20
+//To Determine (i)Head generated by the Pump (ii)Shaft Power required to run the Pump.
+
+ clc
+ clear
+
+//Given Data:-
+ n=3; //Number of Stages
+ Do=400; //Diameter of the Impeller at Outlet, mm
+ bo=20; //Width of Impeller at outlet, mm
+ beta_o=45; //degrees
+ Area_per=10; //Percentage of Total Area which is reduced.
+ eta_o=80/100; //Overall Efficiency
+ eta_man=90/100; //Manometric Efficiency
+ N=1000; //Speed, rpm
+ Q=0.05; //Discharge, m^3/s
+
+
+//Data Used: -
+ rho=1000; //Density of water, kg/m^3
+ g=9.81; //Acceleration due to gravity, m/s^2
+
+
+//Computations:-
+ Do=Do/1000; //m
+ bo=bo/1000; //m
+ A=%pi*Do*bo*(1-Area_per/100); //Actual Area of Flow, m^2
+
+ uo=%pi*Do*N/60; //Tangential Velocity of Impeller at Outlet, m/s
+ Vfo=Q/A; //Velocity of Flow, m/s
+ Vfi= Vfo;
+ Vwo=uo-Vfo/tand(beta_o); //m/s (Value given in book is wrong due to incorrect value of beta_o is used)
+
+ // (i)Head generated by the Pump , H_Tm
+ Hm=eta_man*Vwo*uo/g; //m
+ H_Tm=n*Hm; //m
+
+ //(ii) Shaft Power required to run the Pump , P
+ P=rho*Q*g*H_Tm/(eta_o*1000); //kW
+
+
+//Results:-
+ printf(" (i)Head generated by the Pump , H_Tm=%.2f m \n",H_Tm) //The answer provided in the textbook is wrong
+ printf(" (ii) Shaft Power required to run the Pump , P =%.2f kW \n",P) //The answer provided in the textbook is wrong
+
+