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+//Example 4_5
+clc;funcprot(0);
+//Given data
+P=50000;// kW
+H=225;// m
+N=600;// r.p.m
+h=36;// m
+q=170;// litres/sec
+n_p=0.9;// Over all efficency
+n_m=n_p;
+
+//Calculation
+w=1000*9.81;// N
+Q=(P*1000)/(w*H*n_m);// m^3/s
+// D_r= d/D
+D_r=sqrt(sqrt(h/H)*((Q/q)));
+D=1/D_r;
+p=P*(D_r^2*(h/H)^(3/2));// kW
+n=N*((1/D_r)*(sqrt(h/H)));// r.p.m
+printf('\n(a)The model size is (1/%0.2f)^th of prototype. \n(b)Power developed by the model=%0.1f kW \n(c)Model runner speed=%0.0f r.p.m',D,p,n);
+// The answer provided in the textbook is wrong