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+//Example 4_18
+clc;funcprot(0);
+//Given data
+P=86000;// kW
+N=180;// r.p.m
+H=148;// m
+D=3.4;// m
+Q=66.5;// m^3/sec
+rho=1000;// kg/m^3
+g=9.81;// m/s^2
+
+//Calculation
+N_u=(N*D/sqrt(H));// r.p.m
+P_u=(P/(D^2*H^(3/2)));// kW
+Q_u=(Q/(D^2*(sqrt(H))));// m^3/s
+n_t=((P*1000)/(rho*g*Q*H));// The turbine efficiency
+N_s=((%pi*D*N)/60)*((sqrt(Q*n_t)/(g*H)^(3/4)));// Specific speed
+printf('\nThe unit speed,N_u=%0.0f r.p.m\nThe unit power,P_u=%0.2f kW\nThe unit flow,Q_u=%0.3f m^3/sec\nThe specific speed,N_s=%0.3f',N_u,P_u,Q_u,N_s);
+printf('\nFor this range of specific speed in the SI system,turbine must be francis type');