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+// Example 35_1
+clc;funcprot(0);
+//Given data
+MD=100;// Maximum demand in MW
+md=20;// Minimum demand in MW
+A_1=200;// Rs./kW-year
+A_2=50;// Rs./kW-year
+B_1=0.05;// Rs./kWh
+B_2=0.1;// Rs./kWh
+
+// Calculation
+L=(A_1-A_2)/(B_2-B_1);// Time in hours
+P_b=MD-((L/8760)*(MD-md));// MW
+P_p=100-P_b;// MW
+// (b)
+Area_STbcS=(1/2)*(1000+8760)*(P_p-md);
+Area_bb1c1cb=(8760*md);
+LF_b=((Area_STbcS+Area_bb1c1cb)/(P_p*8760))*100;// Load factor
+A_aTSa=(1/2)*(3000*P_b);
+LF_p=(A_aTSa/(P_p*8760))*100;// Load factor
+printf('\nThe load shared by peak load plant=%0.1f MW \nLoad factor(base load)=%0.0f percentage \nLoad factor(peak load plant)=%0.0f percentage',P_p,LF_b,LF_p);
+// The answer provided in the textbook is wrong