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+// Example 32_8
+clc;funcprot(0);
+//Given data
+L_12=500;// Load in kW
+L_3=200;// Load in kW
+CV=40000;//Calorific value in kJ/kg
+Fc=0.25;// Fuel consumption in kg/kWh
+CF=4000;// Cost of fuel in rupees
+Cf=50;// Plant capacity factor in %
+d=30;// Number of days
+
+//Calculation
+P_c=(2*L_12)+L_3;// Plant capacity in kW
+t=d*24;// Time in hours during the month
+E=(Cf/100)*P_c*t;// Energy generated during the month in kWh/month
+Fc_p=(Fc*E);//Fuel cost per month in kg
+Fc_p=(Fc_p)/1000;// tonnes
+FC=CF*Fc_p;// rupees/month
+Ce=FC/E;// Cost of energy in Rs./kWhr
+O=E*3600;// Output
+I=Fc_p*1000*CV;// Input
+n_o=(O/I)*100;// Over all efficiency
+printf('\nThe over all efficiency of the plant=%0.0f percentage',n_o);