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+// Example 32_20
+clc;funcprot(0);
+//Given data
+P=500;// MW
+F_c=0.45;// Capacity factor
+F_l=0.6;// Annual load factor
+Cf=1000*10^6;// Cost of fuel used/year in rupees
+CC=10000*10^6// Capital cost plant in rupees
+ID=15/100;// Interest and depriciation
+
+// Calculation
+//(a)
+MD=(F_c/F_l)*P;// Maximum demand in MW
+Rc=P-MD;// Reserve capacity in MW
+//(b)
+E=MD*10^3*F_l*8760;// Number of units generated in kW-hrs
+Afc=CC*ID;// Annual fixed charges in rupees
+Arc=Cf;//  Annualrunning charges in rupees
+Tc=Afc+Arc;// Total annual charges in rupees
+C=Tc/E;// Cost of generation (Rs./kW-hr) in rupees
+printf('\n(a)Minimum reserve capacity of the station=%0.0f MW \n(b)The cost per kWh generated=Rs.%0.2f',Rc,C);