1 files changed, 40 insertions, 0 deletions
diff --git a/3733/CH24/EX24.11/Ex24_11.sce b/3733/CH24/EX24.11/Ex24_11.sce
new file mode 100644
index 000000000..f40c1946f
--- /dev/null
+++ b/3733/CH24/EX24.11/Ex24_11.sce
@@ -0,0 +1,40 @@
+// Example 24_11
+clc;funcprot(0);
+//Given data 
+P=5;// Power plant capacity in MW
+T_1=27+273;// K
+p_1=1;// bar
+T_4=1000;// K
+p_r=5;// Pressure ratio
+n_c=0.85;// Isentropic efficiency of compressor
+n_t=0.90;// Isentropic efficiency of turbine
+n_com=0.95;// Combustion efficiency
+n_m=0.95;// Mechanical efficiency
+n_g=0.92;// Generation efficiency
+Tl=10;// Transmission losses
+CV=40000;// kJ/kg
+C_pa=1;// kJ/kg.K
+C_pg=1.1;// kJ/kg.K
+r=1.4;// Specific heat ratio
+m=80;// Air fuel ratio
+Cf_t=5000;// Cost of fuel in Rs./tonne
+Oc=5000;// All other charges in rupees
+
+//Calculation
+n_tt=(1-(Tl/100));// Transmission efficiency
+p_2=p_1*p_r;// bar
+T_2a=T_1*(p_r)^((r-1)/r);// K
+T_2=((T_2a-T_1)/n_c)+T_1;// K
+T_5a=T_4*(p_1/p_2)^((r-1)/r);// K
+T_5=T_4-(n_t*(T_4-T_5a));// K
+e_g=P*1000;// The energy generated per second in kJ/sec
+m_a=(e_g)/((((1+(1/m))*C_pg*(T_4-T_5))-(C_pa*(T_2-T_1)))*n_m*n_g*n_tt);// kg/sec
+T_3=T_4-((CV*n_com)/(C_pg*(m+1)));// K
+e=(C_pa*(T_3-T_2))/(C_pg*(1+(1/m))*(T_5-T_2));// Effectiveness of regenerator
+Fc=(m_a*3600*(1/m));// The fuel consumption per hour in kg/hr
+Cf=(Fc/1000)*Cf_t;// Cost of fuel per hour in Rs.
+Tc=Cf+Oc;// Total cost to be charged per hour in Rs.
+E_g=e_g*1;// Energy generated in kW-hr
+Ce=Tc/E_g;// Charges of energy per kW-hr in Rs./kWh
+printf('\nThe mass of air flow through the compressor per second=%0.2f kg/sec \nThe effectiveness of regenerator=%0.3f \nThe charges of energy per kW-hr=Rs.%0.2f/kWh',m_a,e,Ce);
+// The answers provided in the textbook is wrong