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+// Example 17_3
+clc;funcprot(0);
+//Given data
+P=3000;// kW
+P_1=10;// bar
+T_1=250;// °C
+P_c=65;// cm of Hg
+P_b=75.2;// cm of Hg
+gradT=15;// °C
+T_c=35;// The temperature of the condensate in °C
+C_pw=4.2;// kJ/kg.°C
+
+//Calculation
+//(a)
+p_t=(P_b-P_c)*0.1359;// bar
+p_s=p_t;// bar (as p_a=0)
+// From h-s chart
+x=0.846;// Dryness fraction from h-s chart
+h_1=2984;// kJ/kg
+h_2=2234;// kJ/kg
+h_f2=147;//kJ/kg
+gradh=(h_1-h_2);// kJ/kg
+m_s=P/gradh;// kg/sec
+m_s=m_s*3600;// kg/hr
+SSC=m_s/P;// Specific steam consumption in kg/kW-hr
+//(b)
+n_th=(gradh/(h_1-h_f2))*100;// Thermal efficiency in %
+//(c)
+m_w=(m_s*(h_2-h_f2))/(gradT*C_pw*1000);//Cooling water supplied in tons/hr.
+printf('\n(a)Specific steam consumption=%0.1f kg/kW-hr \n(b)Thermal efficiency of the plant=%0.1f percentage \n(c)Cooling water supplied=%0.0f tons/hr',SSC,n_th,m_w);