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+// Example 17_12
+clc;funcprot(0);
+//Given data
+m_s=10;// Tonnes
+U=4;// KW/m^2.°C
+P=0.2;// bar
+
+//Calculation
+h_fg=2358.3;// Latent heat of steam at 0.2 bar pressure in kJ/kg
+Q=(m_s*1000*h_fg)/3600;//kW
+//The given data is T_s-T_wo=10°C; T_wo-T_wi=20°C;Using this two equations,we get
+Theta_i=30;//°C
+Theta_o=10;//°C
+LMTD=(Theta_i-Theta_o)/(log(Theta_i/Theta_o));//Logrithemic mean temperature difference in °C
+A=Q/(U*LMTD);// m^2
+printf('\nThe area of the condenser required=%0.0f m^2',A);