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+// Example 17_10
+clc;funcprot(0);
+//Given data
+x=0.9;// Dryness fraction
+T_wi=15;//Cooling water inlet temperature °C
+R_air=287;// Nm/kg.K
+R_steam=462.8;// Nm/kg.K
+p_v=61.3;// cm of Hg
+p_b=76;// cm of Hg
+// p_a=0.3*p_t(given)
+C_pw=4.2;// kJ/kg°C
+
+
+// Calculation
+p_t=(p_b-p_v)*0.01359;// bar
+p_a=0.3*p_t;// bar
+p_s=p_t-p_a;// bar
+// From steam tables,Saturation temperature of steam at 0.14 bar
+T_s=52;// °C
+T_m=T_s;// Mixture temperature coming out of condenser in °C
+// From steam tables,At steam pressure of 0.14 bar,
+h_f1=218.4;// kJ/kg
+h_fg1=2381.4;// kJ/kg
+// m=m_w/m_s;
+T_wo=T_s;// °C
+m=((h_f1+(x*h_fg1))-(C_pw*T_s))/(C_pw*(T_wo-T_wi));
+printf('\n(a)Mixture temperature coming out of condenser=%0.0f°C \n(b)Minimum quantity of cooling water required per kg of steam=%0.1f kg',T_m,m);