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+//Chapter 6:Induction Motor Drives
+//Example 16
+clc;
+
+//Variable Initialization
+
+//Ratings of the Delta connected slipring Induction motor
+f=50 // frequency in HZ
+Vl=400 //line voltage in V
+P=6 // number of poles
+SR=2.2 //ratio of stator to rotor
+
+//Parameters referred to the stator
+Xr_=1 // rotor winding reactance in ohm
+Rr_=0.2 // resistance of the rotor windings in ohm
+s=0.04 // given slip when motor runs at full load
+
+//Solution
+Ns=120*f/P //synchronous speed
+Wms=2*%pi*Ns/60
+x=(Rr_/s)**2+Xr_**2
+Tf=(3/Wms)*(Vl)**2*(Rr_/s)/x //full load torque
+K=Tf/(Ns*(1-s))**2
+N=850 //speed of the motor in rpm
+Tl=K*N**2 //torque at the given speed N
+s=(Ns-N)/Ns //slip at the given speed N
+y=Tl*(Wms/3)/Vl**2 //y=X/(X**2+Xr_**2) and X=(Re+Rr_)/s
+
+mprintf("\nThe torque at the given speed of 850rpm is:%d N-m",Tl)
+mprintf("\nWith a slip of s:%.2f",s)
+mprintf("\nTo find the external resistance connected the given quadratic equation is X**2-6.633X+1=0")
+mprintf("\nWith X=(Re-Rr_)/s where Re is the required external resistance")
+
+a = 1
+b = -1/y
+c = 1
+
+//Discriminant
+d = (b**2) - (4*a*c)
+
+X1 = (-b-sqrt(d))/(2*a)
+X2 = (-b+sqrt(d))/(2*a)
+
+//Results
+mprintf("\nThe solutions for X are %.4f and %.4f",X1,X2)
+Re1=X1*s-Rr_
+Re2=X2*s-Rr_
+
+if (Re1>0) then :
+mprintf("\nThe number Re1:%.3f ohm is feasible",abs(Re1))
+R=Re1/SR**2
+mprintf("\nRotor referred value of the external resistance is:%.3f ohm",R)
+end
+
+if (Re2>0) then
+mprintf("\nThen Re2:%.3f ohm is feasible",abs(Re2))
+R=Re2/SR**2
+mprintf("\nHence Rotor referred value of the external resistance is:%.3f ohm",R)
+end