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+//Chapter 13: Fuel and Combustions
+//Problem: 11
+clc;
+
+//Declaration of Variables
+H = 15.4           //in %
+C = 84.6           //in %
+wt_fuel = 1        //in kg
+wt_C = 0.846       //in kg
+wt_H = 0.154       //in kg
+
+// Solution
+mprintf("The combustion reactions are,\n")
+mprintf(" C + O2 --> CO2\n")
+mprintf(" 12  32  \t(by Weight)\n")
+mprintf(" 2H2 + O2 --> H20\n")
+mprintf(" 4    32\t(by Weight)\n")
+
+wt_O = 32 / 12.0 * wt_C
+wt_O_H = 32 / 4.0 * wt_H
+totwt = wt_O + wt_O_H
+totwc=22.4 / 32 * totwt * 1000
+
+mprintf(" Because 32 gm of O2 occupies a volume of 22.4 liters at NTP\n")
+mprintf(" 3.488 * 1000 gm of O2 will occupy %.1f l",totwc)