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+
+clear//
+
+//Variable Declaration
+delta=100 //Increase in the temperature in degreeF
+Load=12000 //Load on the beam in lb
+//Length in inch
+Ls=2*12 //Steel
+Lb=3*12 //Bronze
+//Area in sq.in
+As=0.75 //Steel
+Ab=1.5 //Bronze
+//Modulus of elasticity in psi
+Es=29*10**6 //Steel
+Eb=12*10**6 //Bronze
+//Coefficient of thermal expansion in /degree C
+alpha_s=6.5*10**-6 //Steel
+alpha_b=10**-5 //Bronze
+
+//Calculations
+//Applying the Hookes Law and equilibrium we get two equations
+a=([[Ls*(Es*As)**-1,-Lb*(Eb*Ab)**-1;2,1]])
+b=([(alpha_b*delta*Lb-alpha_s*delta*Ls);Load])
+y=linsolve(a,b)
+
+//Stresses
+sigma_st=-y(1)*As**-1 //Stress in steel in psi (T)
+sigma_br=-y(2)*Ab**-1 //Stress in bronze in psi (C)
+
+//Result
+printf("\n The Stress in steel and bronze are as follows")
+printf("\n %0.3f psi (T) and %0.3f psi(C)",sigma_st,sigma_br)