summaryrefslogtreecommitdiff
path: root/3685/CH9/EX9.17/Ex9_17.sce
diff options
context:
space:
mode:
Diffstat (limited to '3685/CH9/EX9.17/Ex9_17.sce')
-rw-r--r--3685/CH9/EX9.17/Ex9_17.sce52
1 files changed, 52 insertions, 0 deletions
diff --git a/3685/CH9/EX9.17/Ex9_17.sce b/3685/CH9/EX9.17/Ex9_17.sce
new file mode 100644
index 000000000..14999d9bf
--- /dev/null
+++ b/3685/CH9/EX9.17/Ex9_17.sce
@@ -0,0 +1,52 @@
+clc
+// Given
+th1 = 90 // Inlet temperature of hot water in degree Celsius
+tc1 = 25// Inlet temperature of cold water in degree Celsius
+tc2 = 50// Exit temperature of cold water in degree Celsius
+mc = 1 // mass flow rate of cold water in kg/s
+T0 = 300 // Atmospheric temperature in K
+th2p = 60 // Temperature limit in degree Celsius for parallel flow
+th2c = 35 // Temperature limit in degree Celsius for counter flow
+mhp = (tc2-tc1)/(th1-th2p) // mass flow rate of hot water in kg/s for parallel flow
+mhc = (tc2-tc1)/(th1-th2c) // mass flow rate of hot water in kg/s for counter flow
+// At 300 K
+h0 = 113.2 // ENthalpy in kJ/kg
+s0 = 0.395 // ENtropy in kJ/kgK
+T0 = 300 // temperature in K
+// At 90 degree celsius
+h1 = 376.92 // Enthalpy in kJ/kg
+s1 = 1.1925 // Entropy in kJ/kgK
+af1 = mhp*((h1-h0)-T0*(s1-s0)) // Availability
+// Parallel Flow
+// At 60 degree
+h2 = 251.13 // Enthalpy in kJ/kg
+s2 =0.8312 // Entropy in kJ/kgK
+ // At 25 degree
+h3 = 104.89 // Enthalpy in kJ/kg
+s3 = 0.3674 // Entropy in kJ/kgK
+// At 50 degree
+h4 = 209.33 // Enthalpy in kJ/kg
+s4 = 0.7038 // Entropy in kJ/kgK
+REG = mc*((h4-h3)-T0*(s4-s3)) // Rate of energy gain
+REL = mhp*((h1-h2)-T0*(s1-s2)) // Rate of energy loss
+Ia = REL-REG // Energy destruction
+n2a = REG/REL // Second law efficiency
+
+printf("\n Example 9.17")
+printf("\n In parallel flow")
+printf("\n The rate of irreversibility is %f kW",Ia)
+printf("\n The Second law efficiency is %f percent",n2a*100)
+//The answers vary due to round off error
+
+
+// Counter flow
+h2_ = 146.68
+sp = 0.5053 // At 35 degree
+REG_b = REG // Rate of energy gain by hot water is same in both flows
+REL_b = mhc*((h1-h2_)-T0*(s1-sp))
+Ib = mhc*((h1-h2_)-(T0*(s1-sp))) // Energy destruction
+n2b = REG_b/Ib // Second law efficiency
+printf("\n\n In counter flow")
+printf("\n The rate of irreversibility is %f kW",Ib)
+printf("\n The Second law efficiency is %f percent",n2b*100)
+//The answers vary due to round off error