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+clc
+// Given that
+c = 75 // Capacity of classroom in no of perasons
+DBT1 = 10 // Outdoor Dry bulb temperature in degree celsius
+WBT1 = 8 // Outdoor Wet bulb temperature in degree celsius
+DBT2 = 20 // Indoor Dry bulb temperature in degree celsius
+RH2 = 50 // Relative humidity in percentage
+x =0.5 // Bypass factor
+f = 0.3 // Air flow rate per person in cmm
+printf("\n Example 15.10 \n")
+// From the psychrometric chart
+W1 = 0.0058 // In kg moisture/kg d.a.
+h1 = 24.5 // In kJ/kg
+h2 = 39.5 // In kJ/kg
+h3 = h2
+W3 = 0.0074 // In kg moisture/kg d.a.
+t2 = 25 // In degree celsius
+v1 = .81 // In m^3/kg d.a.
+G = f*c/v1
+C = G*(h2-h1)/60
+t4 = (t2-x*DBT1)/(1-x)
+ts = t4
+C_H = G*(W3-W1)*60
+printf("\n Capacity of heating coil is %f kW,\n Surface temperature of heating coil is %d degree celsius,\n Capacity of humidifier is %f kg/h ",C,ts,C_H)
+