8 files changed, 86 insertions, 0 deletions
diff --git a/3685/CH11/EX11.10/Ex11_10.sce b/3685/CH11/EX11.10/Ex11_10.sce
new file mode 100644
index 000000000..92f235c04
--- /dev/null
+++ b/3685/CH11/EX11.10/Ex11_10.sce
@@ -0,0 +1,20 @@
+clc
+R = 0.082 // Gas constant in litre-atm/gmol-K
+m = 1.5 // Mass flow rate in kg/s
+p1 = 1 // Pressure in atm
+t2 = 300 // Temperature after compression in K
+p2 = 400 // Pressure after compression in atm
+Tc = 151 // For Argon in K
+pc = 48 // For Argon in atm
+printf("\n Example 11.10 ")
+a = 0.42748*((R*1000)^2)*((Tc)^2)/pc
+b = 0.08664*(R*1000)*(Tc)/pc
+// By solving equation v2^2 - 49.24*v2^2 + 335.6*v2 - 43440 = 0
+v2 = 56.8 // In cm^3/g mol
+v1 = (R*1000)*(t2)/p1
+delta_h = -1790 // In J/g mol
+delta_s = -57 // In J/g mol
+Q = (t2*delta_s*(10^5)/39.8)/(3600*1000)
+W = Q - (delta_h*(10^5)/39.8)/(3600*1000)
+printf("\n Power required to run the compressor = %f kW, \n The rate at which heat must be removed from the compressor = %f kW",W,Q)
+// Answers vary due to round off error.
diff --git a/3685/CH11/EX11.10/Ex11_10.txt b/3685/CH11/EX11.10/Ex11_10.txt
new file mode 100644
index 000000000..faf4bc622
--- /dev/null
+++ b/3685/CH11/EX11.10/Ex11_10.txt
@@ -0,0 +1,4 @@
+ 
+ Example 11.10 
+ Power required to run the compressor = -10.685371 kW, 
+ The rate at which heat must be removed from the compressor = -11.934673 kW
+\ No newline at end of file
diff --git a/3685/CH11/EX11.3/Ex11_3.sce b/3685/CH11/EX11.3/Ex11_3.sce
new file mode 100644
index 000000000..88d3dcfb9
--- /dev/null
+++ b/3685/CH11/EX11.3/Ex11_3.sce
@@ -0,0 +1,10 @@
+clc
+Tb = 353 // boiling point of benzene in K
+T = 303 // Operational temperature in K
+R = 8.3143 //Gas constant
+P = 101.325*exp((88/R)*(1-(Tb/T)))
+
+printf("\n Example 11.3")
+printf("\n Vapour pressure of benzene is %f kPa",P)
+//The answers vary due to round off error
+
diff --git a/3685/CH11/EX11.3/Ex11_3.txt b/3685/CH11/EX11.3/Ex11_3.txt
new file mode 100644
index 000000000..34909342d
--- /dev/null
+++ b/3685/CH11/EX11.3/Ex11_3.txt
@@ -0,0 +1,3 @@
+ 
+ Example 11.3
+ Vapour pressure of benzene is 17.668259 kPa 
+\ No newline at end of file
diff --git a/3685/CH11/EX11.4/Ex11_4.sce b/3685/CH11/EX11.4/Ex11_4.sce
new file mode 100644
index 000000000..855e897e6
--- /dev/null
+++ b/3685/CH11/EX11.4/Ex11_4.sce
@@ -0,0 +1,15 @@
+clc
+T = (3754-3063)/(23.03-19.49) // Temperature at triple point in K
+P = exp(23.03-(3754/195.2)) // Pressure at triple point
+R = 8.3143 // Gas constant
+Lsub = R*3754 // Latent heat of sublimation
+Lvap = 3063*R // Latent heat of vaporisation
+Lfu = Lsub-Lvap // Latent heat of fusion
+
+printf("\n Example 11.4")
+printf("\n Temperature at triple point is %f K",T)
+printf("\n Pressure at triple point is %f mm Hg",P)
+printf("\n\n Latent heat of sublimation is %d kJ/kg mol",Lsub)
+printf("\n Latent heat of vapourization is is %d kJ/kg mol",Lvap)
+printf("\n Latent heat of fusion is %d kJ/kg mol",Lfu)
+//The answers vary due to round off error
diff --git a/3685/CH11/EX11.4/Ex11_4.txt b/3685/CH11/EX11.4/Ex11_4.txt
new file mode 100644
index 000000000..027784a5a
--- /dev/null
+++ b/3685/CH11/EX11.4/Ex11_4.txt
@@ -0,0 +1,8 @@
+ 
+ Example 11.4
+ Temperature at triple point is 195.197740 K
+ Pressure at triple point is 44.631622 mm Hg
+
+ Latent heat of sublimation is 31211 kJ/kg mol
+ Latent heat of vapourization is is 25466 kJ/kg mol
+ Latent heat of fusion is 5745 kJ/kg mol 
+\ No newline at end of file
diff --git a/3685/CH11/EX11.6/Ex11_6.sce b/3685/CH11/EX11.6/Ex11_6.sce
new file mode 100644
index 000000000..53f1ca192
--- /dev/null
+++ b/3685/CH11/EX11.6/Ex11_6.sce
@@ -0,0 +1,17 @@
+clc
+R = 8.3143 // Gas constant in kJ/kg-mol-K
+N1 = 0.5 // Mole no. of first system
+N2 = 0.75 // Mole no. of second system
+T1 = 200 // Initial temperature of first system in K
+T2 = 300 // Initial temperature of second system in K
+v = 0.02 // Total volume in m^3
+printf("\n Example 11.6\n")
+Tf = (T2*N2+T1*N1)/(N1+N2)
+Uf_1 = (3/2)*(R*N1*Tf)*(10^-3)
+Uf_2 = (3/2)*(R*N2*Tf)*(10^-3)
+pf = (R*Tf*(N1+N2)*(10^-3))/v
+Vf_1 = R*N1*(10^-3)*Tf/pf
+Vf_2 = v-Vf_1
+printf("\n Energy of first system is %f kJ,\n Energy of second system is %f kJ,\n Volume of first system is %f m^3,\n Volume of second system is %f m^3,\n Pressure is %d kN/m^2,\n Temperature is %d K.",Uf_1,Uf_2,Vf_1,Vf_2,pf,Tf)
+//The answers vary due to round off error
+
diff --git a/3685/CH11/EX11.6/Ex11_6.txt b/3685/CH11/EX11.6/Ex11_6.txt
new file mode 100644
index 000000000..15c1262c7
--- /dev/null
+++ b/3685/CH11/EX11.6/Ex11_6.txt
@@ -0,0 +1,9 @@
+ 
+ Example 11.6
+
+ Energy of first system is 1.621288 kJ,
+ Energy of second system is 2.431933 kJ,
+ Volume of first system is 0.008000 m^3,
+ Volume of second system is 0.012000 m^3,
+ Pressure is 135 kN/m^2,
+ Temperature is 260 K. 
+\ No newline at end of file