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+dia=300//in mm
+Asc=8*0.785*20^2//8-20 mm dia bars, in sq mm
+helical_dia=8//in mm
+pitch=25//in mm
+cover=40//in mm
+sigma_cc=5//in MPa
+sigma_sc=130//in MPa
+fck=25//in MPa
+fy=250//in MPa
+Ag=0.785*dia^2//in sq mm
+Ac=Ag-Asc//in sq mm
+P=sigma_cc*Ac + sigma_sc*Asc//in N
+//to find volume of helical reinforcement
+core_dia=dia-2*cover+2*helical_dia//in mm
+l=%pi*core_dia//length of helical steel for one revolution, in mm
+Ab=l*0.785*helical_dia^2/pitch//volume of helical reinforcement per mm height of column, in mm^3
+Ak=0.785*core_dia^2-Asc//in sq mm
+Ac=0.785*core_dia^2//in sq mm
+m=Ab/Ak
+n=0.36*(Ag/Ac-1)*fck/fy
+//as m > n
+P=1.05*P//in N
+mprintf("Safe load=%f kN",P/10^3)