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+b=400//in mm
+D=500//in mm
+Pu=1600//in kN
+Mux=90//in kN-m
+Muy=50//in kN-m
+fck=15//in MPa
+fy=415//in MPa
+p=1.5//assume 1.5% steel, placed on four sides
+m=p/fck
+c=50//cover (assume), in mm
+//to find Mux1
+n=c/D//n=d'/D
+l=Pu*10^3/fck/b/D
+//referring to Fig.19.20, for Pu/ fck/ b/ D = 0.53 and p/ fck = 0.1
+f=0.09
+Mux1=f*fck*b*D^2/10^6//in kN-m
+//to find Muy1
+b=500//in mm
+D=400//in mm
+n=c/D//n=d'/D
+l=Pu*10^3/fck/b/D
+//referring to Fig.19.21, for Pu/ fck/ b/ D = 0.53 and p/ fck = 0.1
+f=0.08
+Muy1=f*fck*b*D^2/10^6//in kN-m
+Puz=(0.45*fck*(1-p/100)*b*D+0.75*fy*p/100*b*D)/10^3//in kN
+a=Pu/Puz//<0.8
+an=1+1/0.6*(a-0.2)
+r=(Mux/Mux1)^an+(Muy/Muy1)^an//<1
+Asc=p/100*b*D//in sq mm
+//provide 6-16 mm + 6-20 mm dia bars
+Asc=6*0.785*16^2+6*0.785*20^2//in sq mm
+mprintf("Summary of design:\nColumn size - %d x %d mm\nSteel-main = 6-16 mm + 6-20 mm dia bars",D,b)
+//answer in textbook is incorrect