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+Df=100//in mm
+bf=1500//in mm
+bw=300//in mm
+d=600//in mm
+Ast=4500//in sq mm
+fy=415//in MPa
+fck=20//in MPa
+Asf=round(0.36*fck*bf*Df/0.87/fy)//area of steel required for flange, in sq mm
+//as Ast>Asf, Xu>Df
+Xu=(0.87*fy*Ast-0.446*fck*(bf-bw)*Df)/0.36/fck/bw//in mm
+Xc=0.479*d//Xc>Xu; hence OK
+a=0.43*Xu//as Df<0.43 Xu, stress in flange is uniform
+Mu=(0.36*fck*bw*Xu*(d-0.416*Xu)+0.446*fck*(bf-bw)*Df*(d-Df/2))/10^6//in kN-m
+mprintf("Moment of resistance of T-beam=%f kN-m",Mu)